详解用C语言实现三子棋游戏流程
如果你想用C语言实现三子棋游戏,那么你需要考虑以下几步:
1. 创建游戏棋盘
首先,你需要创建一个9个元素的棋盘数组,用于存储游戏中的棋子。“x”代表玩家1,”o”代表玩家2,“ ”(空格)代表该位置没有落子。以下是创建棋盘的代码示例:
char board[9] = {' ', ' ', ' ', ' ', ' ', ' ', ' ', ' ', ' '};
2. 游戏流程
游戏流程可以分为以下几个部分:
2.1. 绘制棋盘
游戏开始时,需要输出棋盘。以下是绘制棋盘的代码示例:
void draw_board(char board[])
{
printf(" %c | %c | %c\n", board[0], board[1], board[2]);
printf("-----------\n");
printf(" %c | %c | %c\n", board[3], board[4], board[5]);
printf("-----------\n");
printf(" %c | %c | %c\n", board[6], board[7], board[8]);
}
2.2. 玩家落子
每一轮游戏开始前,需要判断当前玩家落棋的合法性,并在玩家决定落子位置后更新棋盘。以下是代码示例:
void player_move(char board[], char player_char)
{
int move;
printf("Player %c enter your move (0-8): ", player_char);
scanf("%d", &move);
if (board[move] == ' ') {
board[move] = player_char;
} else {
printf("Invalid move, try again.\n");
player_move(board, player_char);
}
}
2.3. 判断胜负
每一次玩家落子后,需要判断是否有玩家胜利。以下是代码示例:
int has_won(char player_char, char board[])
{
if ((board[0] == player_char && board[1] == player_char && board[2] == player_char) ||
(board[3] == player_char && board[4] == player_char && board[5] == player_char) ||
(board[6] == player_char && board[7] == player_char && board[8] == player_char) ||
(board[0] == player_char && board[3] == player_char && board[6] == player_char) ||
(board[1] == player_char && board[4] == player_char && board[7] == player_char) ||
(board[2] == player_char && board[5] == player_char && board[8] == player_char) ||
(board[0] == player_char && board[4] == player_char && board[8] == player_char) ||
(board[2] == player_char && board[4] == player_char && board[6] == player_char)) {
return 1;
} else {
return 0;
}
}
2.4. 游戏结束
当一方玩家胜利或者平局时,游戏结束。以下是代码示例:
int is_game_over(char board[])
{
int i;
for (i = 0; i < 9; i++) {
if (board[i] == ' ') {
return 0;
}
}
return 1;
}
3. 示例
下面是一个完整的示例代码:
#include <stdio.h>
void draw_board(char []);
void player_move(char [], char);
int has_won(char, char []);
int is_game_over(char []);
int main(void)
{
char board[9] = {' ', ' ', ' ', ' ', ' ', ' ', ' ', ' ', ' '};
char player_char = 'x';
int game_over = 0;
while (! game_over) {
draw_board(board);
player_move(board, player_char);
if (has_won(player_char, board)) {
game_over = 1;
printf("Player %c has won the game.\n", player_char);
} else if (is_game_over(board)) {
game_over = 1;
printf("The game is a tie.\n");
} else {
if (player_char == 'x') {
player_char = 'o';
} else {
player_char = 'x';
}
}
}
return 0;
}
void draw_board(char board[])
{
printf(" %c | %c | %c\n", board[0], board[1], board[2]);
printf("-----------\n");
printf(" %c | %c | %c\n", board[3], board[4], board[5]);
printf("-----------\n");
printf(" %c | %c | %c\n", board[6], board[7], board[8]);
}
void player_move(char board[], char player_char)
{
int move;
printf("Player %c enter your move (0-8): ", player_char);
scanf("%d", &move);
if (board[move] == ' ') {
board[move] = player_char;
} else {
printf("Invalid move, try again.\n");
player_move(board, player_char);
}
}
int has_won(char player_char, char board[])
{
if ((board[0] == player_char && board[1] == player_char && board[2] == player_char) ||
(board[3] == player_char && board[4] == player_char && board[5] == player_char) ||
(board[6] == player_char && board[7] == player_char && board[8] == player_char) ||
(board[0] == player_char && board[3] == player_char && board[6] == player_char) ||
(board[1] == player_char && board[4] == player_char && board[7] == player_char) ||
(board[2] == player_char && board[5] == player_char && board[8] == player_char) ||
(board[0] == player_char && board[4] == player_char && board[8] == player_char) ||
(board[2] == player_char && board[4] == player_char && board[6] == player_char)) {
return 1;
} else {
return 0;
}
}
int is_game_over(char board[])
{
int i;
for (i = 0; i < 9; i++) {
if (board[i] == ' ') {
return 0;
}
}
return 1;
}
上述代码实现了一个支持两个玩家玩家的三子棋游戏,程序会在每个人的回合询问棋子的下落位置,当一方取得胜利或者平局时,程序结束。
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