使用Python实现一个简单的项目监控

使用Python实现一个简单的项目监控可以分为以下步骤：

1. 安装需要的Python包
2. 读取配置文件
3. 发送HTTP请求并获取响应
4. 解析响应并进行判断
5. 根据监控结果发送邮件或者短信提醒

一、安装需要的Python包

我们需要使用到requests和configparser两个Python包，其中requests用于发送HTTP请求，configparser用于读取配置文件。可以使用pip来安装这两个包，命令如下：

pip install requests configparser

二、读取配置文件

使用配置文件可以方便地修改监控的对象和参数，因此在实现项目监控时需要读取配置文件中的信息。我们可以将配置文件写成ini配置文件，格式如下：

[monitor]
url=http://www.example.com
interval=300
timeout=10

其中，url表示要监控的网址，interval表示每隔多少秒进行一次检测，timeout表示每次HTTP请求的超时时间。

我们可以使用configparser库来读取配置文件，代码如下：

import configparser

config = configparser.ConfigParser()
config.read('config.ini')
url = config.get('monitor', 'url')
interval = int(config.get('monitor', 'interval'))
timeout = int(config.get('monitor', 'timeout'))

三、发送HTTP请求并获取响应

监控项目需要定期发送HTTP请求并获取响应，以判断目标网站的状态。我们可以使用requests库来发送HTTP请求和获取响应，代码如下：

import requests

response = requests.get(url, timeout=timeout)
status_code = response.status_code

四、解析响应并进行判断

根据HTTP请求的响应，我们可以判断目标网站的状态是否正常。如果状态码为200，则返回正常，否则返回异常。代码如下：

if status_code == 200:
    print('[INFO] The website %s is working normally.' % url)
else:
    print('[ERROR] The website %s is NOT working properly.' % url)

五、根据监控结果发送邮件或者短信提醒

根据监控结果，我们可以选择向管理员发送邮件或短信提醒。这里我们使用smtplib库来发送邮件。代码如下：

import smtplib
from email.mime.text import MIMEText
from email.header import Header

def send_mail(status_code):
    mail_host = 'smtp.example.com'
    mail_user = '[e-mail]'
    mail_pass = 'password'

    sender = '[e-mail]'
    receivers = ['[e-mail]']

    if status_code == 200:
        subject = '[INFO] The website %s is working normally.' % url
    else:
        subject = '[ERROR] The website %s is NOT working properly.' % url

    message = MIMEText(subject, 'plain', 'utf-8')
    message['From'] = Header("Admin", 'utf-8')
    message['To'] = Header("Admin", 'utf-8')
    message['Subject'] = Header(subject, 'utf-8')

    try:
        smtpObj = smtplib.SMTP()
        smtpObj.connect(mail_host, 25)
        smtpObj.login(mail_user, mail_pass)

        smtpObj.sendmail(sender, receivers, message.as_string())
        print("Successfully sent email")
    except smtplib.SMTPException as e:
        print("Error: unable to send email")

以上就是使用Python实现一个简单的项目监控的完整攻略。接下来我们给出两个示例：

1. 监控百度网站

[monitor]
url=https://www.baidu.com
interval=300
timeout=10

import configparser
import requests
import smtplib
from email.mime.text import MIMEText
from email.header import Header

# 读取配置文件
config = configparser.ConfigParser()
config.read('config.ini')
url = config.get('monitor', 'url')
interval = int(config.get('monitor', 'interval'))
timeout = int(config.get('monitor', 'timeout'))

# 发送HTTP请求并获取响应
response = requests.get(url, timeout=timeout)
status_code = response.status_code

# 解析响应并进行判断
if status_code == 200:
    print('[INFO] The website %s is working normally.' % url)
else:
    print('[ERROR] The website %s is NOT working properly.' % url)

# 发送邮件
mail_host = 'smtp.example.com'
mail_user = '[e-mail]'
mail_pass = 'password'

sender = '[e-mail]'
receivers = ['[e-mail]']

if status_code == 200:
    subject = '[INFO] The website %s is working normally.' % url
else:
    subject = '[ERROR] The website %s is NOT working properly.' % url

message = MIMEText(subject, 'plain', 'utf-8')
message['From'] = Header("Admin", 'utf-8')
message['To'] = Header("Admin", 'utf-8')
message['Subject'] = Header(subject, 'utf-8')

try:
    smtpObj = smtplib.SMTP()
    smtpObj.connect(mail_host, 25)
    smtpObj.login(mail_user, mail_pass)

    smtpObj.sendmail(sender, receivers, message.as_string())
    print("Successfully sent email")
except smtplib.SMTPException as e:
    print("Error: unable to send email")

1. 监控新浪微博

[monitor]
url=https://www.weibo.com
interval=60
timeout=5

import configparser
import requests
import smtplib
from email.mime.text import MIMEText
from email.header import Header

# 读取配置文件
config = configparser.ConfigParser()
config.read('config.ini')
url = config.get('monitor', 'url')
interval = int(config.get('monitor', 'interval'))
timeout = int(config.get('monitor', 'timeout'))

# 发送HTTP请求并获取响应
response = requests.get(url, timeout=timeout)
status_code = response.status_code

# 解析响应并进行判断
if status_code == 200:
    print('[INFO] The website %s is working normally.' % url)
else:
    print('[ERROR] The website %s is NOT working properly.' % url)

# 发送邮件
mail_host = 'smtp.example.com'
mail_user = '[e-mail]'
mail_pass = 'password'

sender = '[e-mail]'
receivers = ['[e-mail]']

if status_code == 200:
    subject = '[INFO] The website %s is working normally.' % url
else:
    subject = '[ERROR] The website %s is NOT working properly.' % url

message = MIMEText(subject, 'plain', 'utf-8')
message['From'] = Header("Admin", 'utf-8')
message['To'] = Header("Admin", 'utf-8')
message['Subject'] = Header(subject, 'utf-8')

try:
    smtpObj = smtplib.SMTP()
    smtpObj.connect(mail_host, 25)
    smtpObj.login(mail_user, mail_pass)

    smtpObj.sendmail(sender, receivers, message.as_string())
    print("Successfully sent email")
except smtplib.SMTPException as e:
    print("Error: unable to send email")