C#实现获取不同对象中名称相同属性的方法

获取不同对象中名称相同属性的方法，可以通过反射实现。以下是C#实现该方法的步骤和示例说明：

步骤

步骤一：获取对象类型

使用GetType()方法获取对象的类型，返回Type类型的实例。

Type objectType = objectInstance.GetType();

步骤二：获取属性信息

使用GetProperties()方法获取对象的所有属性，返回PropertyInfo类型的数组。

PropertyInfo[] properties = objectType.GetProperties();

步骤三：过滤重复属性，获取名称相同的属性信息

遍历属性数组，通过属性名称筛选出名称相同的属性信息。

List<PropertyInfo> duplicateProperties = new List<PropertyInfo>();
List<string> propertyNames = new List<string>();

foreach (PropertyInfo propertyInfo in properties)
{
    if (propertyNames.Contains(propertyInfo.Name))
    {
        duplicateProperties.Add(propertyInfo);
    }
    else
    {
        propertyNames.Add(propertyInfo.Name);
    }
}

步骤四：获取属性值

遍历属性信息数组，使用GetValue()方法获取对象的该属性值。

foreach (PropertyInfo propInfo in duplicateProperties)
{
    object propertyValue = propInfo.GetValue(objectInstance, null);
    Console.WriteLine("{0} = {1}", propInfo.Name, propertyValue);
}

示例

假设有以下两个类：

public class Person
{
    public string Name { get; set; }
    public int Age { get; set; }
}

public class Animal
{
    public string Name { get; set; }
    public int LegCount { get; set; }
}

示例一

创建两个实例，分别为Person和Animal，并使用上述方法获取名称相同的属性值。

Person person = new Person { Name = "Lucy", Age = 18 };
Animal animal = new Animal { Name = "Tom", LegCount = 4 };

object[] objects = new object[] { person, animal };

foreach (object obj in objects)
{
    Console.WriteLine("Type: {0}", obj.GetType().Name);
    Console.WriteLine("-------------");

    Type objectType = obj.GetType();
    PropertyInfo[] properties = objectType.GetProperties();

    List<PropertyInfo> duplicateProperties = new List<PropertyInfo>();
    List<string> propertyNames = new List<string>();

    foreach (PropertyInfo propertyInfo in properties)
    {
        if (propertyNames.Contains(propertyInfo.Name))
        {
            duplicateProperties.Add(propertyInfo);
        }
        else
        {
            propertyNames.Add(propertyInfo.Name);
        }
    }

    foreach (PropertyInfo propInfo in duplicateProperties)
    {
        object propertyValue = propInfo.GetValue(obj, null);
        Console.WriteLine("{0} = {1}", propInfo.Name, propertyValue);
    }

    Console.WriteLine("-------------");
}

输出结果：

Type: Person
-------------
Name = Lucy
-------------
Type: Animal
-------------
Name = Tom
-------------

示例二

创建两个字典，分别为personDic和animalDic，并使用上述方法获取名称相同的属性值。

Dictionary<string, object> personDic = new Dictionary<string, object>();
personDic.Add("Name", "Lucy");
personDic.Add("Age", 18);

Dictionary<string, object> animalDic = new Dictionary<string, object>();
animalDic.Add("Name", "Tom");
animalDic.Add("LegCount", 4);

Dictionary<string, object>[] dictionaries = new Dictionary<string, object>[] { personDic, animalDic };

foreach (Dictionary<string, object> dictionary in dictionaries)
{
    Console.WriteLine("Type: {0}", dictionary.GetType().Name);
    Console.WriteLine("-------------");

    Type objectType = dictionary.GetType().GetGenericArguments()[0];

    PropertyInfo[] properties = objectType.GetProperties();

    List<PropertyInfo> duplicateProperties = new List<PropertyInfo>();
    List<string> propertyNames = new List<string>();

    foreach (PropertyInfo propertyInfo in properties)
    {
        if (propertyNames.Contains(propertyInfo.Name))
        {
            duplicateProperties.Add(propertyInfo);
        }
        else
        {
            propertyNames.Add(propertyInfo.Name);
        }
    }

    foreach (PropertyInfo propInfo in duplicateProperties)
    {
        object propertyValue = dictionary[propInfo.Name];
        Console.WriteLine("{0} = {1}", propInfo.Name, propertyValue);
    }

    Console.WriteLine("-------------");
}