C语言实现简单三子棋程序

C语言实现简单三子棋程序的完整攻略包括以下步骤：

1. 定义游戏规则和棋盘

首先需要定义游戏规则，规定每个玩家的棋子形状和放置的位置等信息。同时需要定义一个3x3的棋盘数组，用于记录每个位置上的棋子情况。

#include <stdio.h>

#define ROW 3
#define COL 3

// 定义棋盘
char board[ROW][COL] = {
    {' ', ' ', ' '},
    {' ', ' ', ' '},
    {' ', ' ', ' '}
};

void print_board()
{
    printf("  1   2   3\n");
    printf("1 %c | %c | %c \n", board[0][0], board[0][1], board[0][2]);
    printf(" ---|---|---\n");
    printf("2 %c | %c | %c \n", board[1][0], board[1][1], board[1][2]);
    printf(" ---|---|---\n");
    printf("3 %c | %c | %c \n", board[2][0], board[2][1], board[2][2]);
}

1. 实现玩家交替落子

按照游戏规则和棋盘的定义，玩家交替进行游戏。需要实现一个函数，根据玩家输入的行列数目，判断该位置是否可以下子，如果可以，就在对应位置上放置该玩家的棋子，并更新棋盘。同时需要判断游戏是否结束，如果棋盘已经填满或者某个玩家已经连成三个棋子，就宣告游戏结束。

int is_full()
{
    int i, j;
    for (i = 0; i < ROW; i++) {
        for (j = 0; j < COL; j++) {
            if (board[i][j] == ' ')
                return 0;
        }
    }
    return 1;
}

int check_win(char c)
{
    int i;
    for (i = 0; i < ROW; i++) {
        if (board[i][0] == c && board[i][1] == c && board[i][2] == c)
            return 1;
        if (board[0][i] == c && board[1][i] == c && board[2][i] == c)
            return 1;
    }
    if (board[0][0] == c && board[1][1] == c && board[2][2] == c)
        return 1;
    if (board[0][2] == c && board[1][1] == c && board[2][0] == c)
        return 1;
    return 0;
}

void play_game()
{
    int row, col;
    char c = 'X';

    while (1) {
        printf("Player %c's turn:\n", c);
        printf("Please input row and col (e.g. 1 2):\n");
        scanf("%d %d", &row, &col);

        if (row < 1 || row > 3 || col < 1 || col > 3) {
            printf("Invalid input, please input valid row and col (1~3):\n");
            continue;
        }

        if (board[row-1][col-1] != ' ') {
            printf("The place has already been taken, please input again:\n");
            continue;
        }

        board[row-1][col-1] = c;
        print_board();

        if (check_win(c)) {
            printf("Player %c wins!\n", c);
            break;
        }

        if (is_full()) {
            printf("Game ends in a draw!\n");
            break;
        }

        if (c == 'X')
            c = 'O';
        else
            c = 'X';
    }
}

1. 进行游戏并输出结果

在主函数中，调用上述三个子函数，依次执行游戏规则、玩家交替落子和胜负判断等操作。

int main(void)
{
    printf("Welcome to the 3x3 Tic-tac-toe game!\n");
    print_board();
    play_game();
    return 0;
}

1. 示例1

假设玩家1执黑子，玩家2执白子，依次放置棋子如下：

Welcome to the 3x3 Tic-tac-toe game!
  1   2   3
1   |   |   
 ---|---|---
2   |   |   
 ---|---|---
3   |   |   
Player X's turn:
Please input row and col (e.g. 1 2):
1 1
  1   2   3
1 X |   |   
 ---|---|---
2   |   |   
 ---|---|---
3   |   |   
Player O's turn:
Please input row and col (e.g. 1 2):
2 2
  1   2   3
1 X |   |   
 ---|---|---
2   | O |   
 ---|---|---
3   |   |   
Player X's turn:
Please input row and col (e.g. 1 2):
1 2
  1   2   3
1 X | X |   
 ---|---|---
2   | O |   
 ---|---|---
3   |   |   
Player O's turn:
Please input row and col (e.g. 1 2):
3 3
  1   2   3
1 X | X |   
 ---|---|---
2   | O |   
 ---|---|---
3   |   | O 
Player X's turn:
Please input row and col (e.g. 1 2):
2 3
  1   2   3
1 X | X |   
 ---|---|---
2   | O | X 
 ---|---|---
3   |   | O 
Player O's turn:
Please input row and col (e.g. 1 2):
3 1
  1   2   3
1 X | X |   
 ---|---|---
2   | O | X 
 ---|---|---
3 O |   | O 
Player X's turn:
Please input row and col (e.g. 1 2):
2 1
  1   2   3
1 X | X |   
 ---|---|---
2 X | O | X 
 ---|---|---
3 O |   | O 
Player X wins!

输出结果为“Player X wins!”，表示玩家1胜利。

1. 示例2

假设玩家1执白子，玩家2执黑子，依次放置棋子如下：

Welcome to the 3x3 Tic-tac-toe game!
  1   2   3
1   |   |   
 ---|---|---
2   |   |   
 ---|---|---
3   |   |   
Player O's turn:
Please input row and col (e.g. 1 2):
1 1
  1   2   3
1 O |   |   
 ---|---|---
2   |   |   
 ---|---|---
3   |   |   
Player X's turn:
Please input row and col (e.g. 1 2):
2 2
  1   2   3
1 O |   |   
 ---|---|---
2   | X |   
 ---|---|---
3   |   |   
Player O's turn:
Please input row and col (e.g. 1 2):
1 2
  1   2   3
1 O | O |   
 ---|---|---
2   | X |   
 ---|---|---
3   |   |   
Player X's turn:
Please input row and col (e.g. 1 2):
2 1
  1   2   3
1 O | O |   
 ---|---|---
2 X | X |   
 ---|---|---
3   |   |   
Player O's turn:
Please input row and col (e.g. 1 2):
1 3
  1   2   3
1 O | O | O 
 ---|---|---
2 X | X |   
 ---|---|---
3   |   |   
Player O wins!

输出结果为“Player O wins!”，表示玩家1失败。

以上就是用C语言实现简单三子棋程序的完整攻略。