# coding=gbk


from bs4 import BeautifulSoup
import requests
import urllib
x = 1
y = 1

def crawl(url):
    res = requests.get(url)
    soup = BeautifulSoup(res.text, 'html.parser')
    global y
    with open(f'F:/pachong/xnt/{y}.txt','w',encoding="utf-8") as f:
        f.write(str(soup))
        y += 1
    yinhuns = soup.select('img')
    print(yinhuns)
    for yh in yinhuns:
        print(yh)
        link = yh.get('src')
        print(link)
        global x    
        urllib.request.urlretrieve(link, f'F:/pachong/xnt/{x}.jpg')
        print(f'正在下载第{x}张图片')
        x += 1
        
for i in range(1,5):
    url = "https://acg.fi/hentai/23643.htm/" + str(i)
    
    try:
        crawl(url)
    except ValueError as f:
        continue
    except Exception as e:
        print(e)
  • 运行程序过程中返回下面结果
<img alt="A区(ACG.Fi)" class="logo" src="https://acg.fi/logo.png"/>
https://acg.fi/logo.png
HTTP Error 403: Forbidden
  • 问题有三个

    • 搜索src值的时候,没有搜索到全部符合要找的图片网址
    • 返回的第一个网址出现了403错误,拒绝访问
    • soup.select返回的不是正确的list
  • 思考

    • 有可能所要找的网址中包含中文,无法编译
    • 如果通过正则对,请求的url的text进行,筛选
#coding=gbk
from bs4 import BeautifulSoup
import requests
import urllib
x = 1


def crawl(url, header):
	
    res = requests.get(url, headers=header)
    soup = BeautifulSoup(res.text, 'html.parser')
    
    yinhuns = soup.find('div', attrs = {'id':"content-innerText"}).find_all('img',limit=4)
    print(yinhuns)
    
    for yh in yinhuns:
        
        link = yh.get('src')
        global x
        print(x)
        urllib.request.urlretrieve(link, 'F:/pachong/xnt/{}.jpg'.format(x))
        print('正在下载第{0}张图片'.format(x))
        x += 1


header = {
		"User-Agent":"Mozilla/5.0 (Windows NT 10.0; WOW64) AppleWebKit/537.36 (KHTML, like Gecko) Chrome/58.0.3029.110 Safari/537.36 SE 2.X MetaSr 1.0"
			}       
for i in range(1,5):	
    url = "https://acg.fi/hentai/23643.htm/" + str(i)
    
    try:
        crawl(url, header)
    except ValueError as f:
        continue
    except Exception as e:
        print(e)
  • 这个过程用了find(),find_all()方法,依旧没有解决list的问题
  • 后续过程使用urllib.parse.quote对中文部分重新编码,但是urllib.request.urlretrieve依然报错
  • 重新修改后
#coding=gbk

import requests
import urllib
import re
from PIL import Image
from io import BytesIO
x = 1 

# 获取抓取的图片源网址
def crawl(url, header):
    
    res = requests.get(url, headers=header)
    # 防止被反爬,打开后关闭
    res.close()
    res = res.text
    pattern = re.compile('http.*?apic.*?jpg')
    result = re.findall(pattern, res)
    return result

# 对重编码的网址下载图片
def down(outs, folder_path):
	global x
	for out in outs:
		# 获取新编码的URL地址
		res = requests.get(out)
		# 防止被反爬,打开后关闭
		res.close()
		bf = BytesIO()
		bf.write(res.content)
		img = Image.open(bf)
		print(f'正在下载第{x}张图片')
		img.save(folder_path + f"{x}.jpg")
		x += 1

# 对获取的图片源网址进行重编码
def bianma(results):
	outs = []
	for s in results:
		# 用正则筛选出中文部分
		pattern = re.compile('[\u4e00-\u9fa5]+')
		result = re.search(pattern, s)
		su = result.group(0)
		# 把中文部分重洗编码
		li = urllib.parse.quote(su)
		# 把原URL地址中文部分替换成编码后的
		out = re.sub(pattern, li, s)
		outs.append(out)
	# 对列表进行去重并且按照原来的次序排列
	outs_cp = sorted(set(outs), key=outs.index)	
	return outs_cp

def main():
	try:
		header = {
				"User-Agent":"Mozilla/5.0 (Windows NT 10.0; WOW64) AppleWebKit/537.36 (KHTML, like Gecko) Chrome/58.0.3029.110 Safari/537.36 SE 2.X MetaSr 1.0"
					}
		folder_path = 'F:/pachong/xnt/'
		for i in range(1,5):
			url = "https://acg.fi/hentai/23643.htm/" + str(i)
			results = crawl(url, header)
			outs = bianma(results)
			down(outs, folder_path)
	except Exception as e:
		print(e)

if __name__ == '__main__':
	main()
  • 对于图片路径中有中文的,可以使用BytesIO和PIL下载图片,证实可以有效解决
  • 几次试验出现[Errno 10054] 远程主机强迫关闭了一个现有的连接,可以在requests.get()后使用close()
  • 程序运行无误,就是有点慢,后期可以使用多线程尝试